(1/2)^3x+1=(1/2)^5x-1

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Solution for (1/2)^3x+1=(1/2)^5x-1 equation: 



(1/2)^3x+1=(1/2)^5x-1

We move all terms to the left:

(1/2)^3x+1-((1/2)^5x-1)=0



Domain of the equation: 2)^3x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)^5x-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)^3x-((+1/2)^5x-1)+1=0

We calculate fractions


2^5x/2^3x*2)^5x-1))+(-2^3x/2^3x*2)^5x-1))+1=0

We can not solve this equation

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